Post Your Answer
Post Your Answer
Ans 1:
Class : Class 4
Heads ( Lions + Peacocks) = 15, No. of Legs = 25 +15 = 40. Since total legs were 40 no. of lions has to be less than 10 (because 10 x 4 legs = 40 which means zero peacock, which is not possible...) . so if we take 5 lions and 10 peacocks, total heads = 15 & total legs = 5 x 4 + 10 x 2 = 40 legs. Thus the answer is 5 peacocks were more than lions.
Ans 2:
Class : Class 10
Answer : D
Solution
Let number of peacocks be p
Let number of lions be l
Number of legs = 15
Number of heads = 15 + 25 = 40
p + l = 15
2p + 4l = 40
Solving the above equations
p = 10 , l = 5
So there are 5 more peacocks than lions.
Solution
Let number of peacocks be p
Let number of lions be l
Number of legs = 15
Number of heads = 15 + 25 = 40
p + l = 15
2p + 4l = 40
Solving the above equations
p = 10 , l = 5
So there are 5 more peacocks than lions.
Post Your Answer
Post Your Answer
Post Your Answer
?
Post Your Answer
= 2309, 5 
= 4365 and 
= 1927, then find the value of 5 
Post Your Answer
Ans 2:
Class : Class 10
Thank you for pointing out the mistake. We have corrected the sequence now.
Water in the jug = 1/12
Water added in the jug = 5/6
Total water = 1/2 + 5/6 = 11/12
Water overflowed = 1/4
Capacity of jug = 11/12 - 1/4 = 8/12 = 2/3 L
Water in the jug = 1/12
Water added in the jug = 5/6
Total water = 1/2 + 5/6 = 11/12
Water overflowed = 1/4
Capacity of jug = 11/12 - 1/4 = 8/12 = 2/3 L