Ans 1:
Class : Class 4
ans a-80. From 1-9 there are 9 digits . so we are left with 151-9=142 digits. Note that from 10 onwards all numbers are of 2 digits. So there are 142/2=71 numbers to have 142 digits. Therefore there are 9+71=80 numbers.
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Ans 1:
Class : Class 5
_____________ is a factor of 7th multiple of 43.
Solution:7th multiple of 43=43*7=301
As,4,5,6 are not but 7 is divisible:301/7=43
So,correct answer is no.:D(7)