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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
Ans is 84. Area of the square = 12 x 12 = 144 which means 12 is the length of two sides of the square, therefore each side will be 6 and there are 14 sides. Hence the perimeter is 14 x 6 = 84

Ans 2:

Class : Class 5
Option A 84 m is the right answer. Solution : The area of square is 144 m as given. Hence, the side of square is 12 m. The length of one smaller square in the shaded square is 6 m. Hence the length of the rectangle is 6+6+6+6 =24 the breadth of rectangle is 6+6+6=18 The perimetre of rectangle is 2(l+b) = 2 (24+18) = 2*42 = 84 m

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
ans-d

Ans 2:

Class : Class 4
ooliooli

Ans 3:

Class : Class 6

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
answer c.5+4+1=10.add 10 with 12.but the sum is wrong as per snakes and lader

Ans 2:

Class : Class 10
The correct answer is 14.

Ans 3:

Class : Class 6
actually the answer should be 14 but now he is on 10

Ans 4:

Class : Class 6
Answer is supposed to be 14 , but they are NOT counting the going down through the snake ,so in that case answer should be 22[c].

Ans 5:

Class : Class 5
Yes, I agree with you. The answer should have been 14.

Ans 6:

Class : Class 6
correct answer is 14..

Ans 7:

Class : Class 4
They keep changing the answers. I call it "cheating "

Ans 8:

Class : Class 4
22

Ans 9:

Class : Class 6
Answer is supposed to be 14 , but they are NOT counting the going down through the snake ,so in that case answer should be 22[c].

Ans 10:

Class : Class 4

Ans 11:

Class : Class 9
it should be 14

Ans 12:

Class : Class 7
answer c easy quetion

Ans 13:

Class : Class 6
Naman from DPS Mathura road DelhiI agree with you all ,answer should be 14

Ans 14:

Class : Class 4
They keep changing answers. It is called "cheating".

Ans 15:

Class : Class 6
IF WE TAKE 1st 4 THEN 5 AND THEN AT LAST 1 THEN IT WILL COME 22 AND PLEASE START COUNTING FROM 13 NOT FROM 11

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 9
c

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4

Ans 2:

Class : Class 4
your answer is wrong the correct answer is ans3

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 6
If large square = A small square =B cylinder=C then, A+B=70gm 10A+10B=700gm 10C=3200gm-700gm =2500gm C=2500/10 =250

Ans 2:

Class : Class 9
a

Ans 3:

Class : Class 4
A

Ans 4:

Class : Class 4

Ans 5:

Class : Class 5
A

Ans 6:

Class : Class 8

Ans 7:

Class : Class 4
answer is A

Ans 8:

Class : Class 8
250 GRAMS . FIRST DIVIDE 3200 BY 10 . ANS =320 THEN SUBTRACT 70 FROM 320. ANS =250 WEIGHT OF THE CYLINDER =250

Ans 9:

Class : Class 4
A

Ans 10:

Class : Class 7
a+b=70g 10a+10b+10c=3200 10(a+b+c)=3200 a+b+c=320 c=320-70=250

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 7
C

Ans 2:

Class : Class 4

Ans 3:

Class : Class 4

Ans 4:

Class : Class 4
A- EMI 1970 per month 3 years = 36 months Total Amount Paid in three years 36 x 1970 = 70920 B - Rajat Paid Advance - 35000 Total Amount Paid A +B 70920+35000= 105920 Answer is C

Ans 5:

Class : Class 4
3years=36 monthsEMIper month=1970EMI in three year=72920Rajat paid in advance=35000Total amount paid=70920 35000=105920......[C] is the answer............................

Ans 6:

Class : Class 8
3 years = 36 months, and EMI paid each month= 1970/-, so the total amount paid in EMI is 36 x 1970, which is 70920. Therefore, total value of the car is 35000 + 70920 = 105920/-.

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
answer is 10 and 5

Ans 2:

Class : Class 4
Common factor is 5,10

Ans 3:

Class : Class 10
SORRY THE ANSWER IS A

Ans 4:

Class : Class 4
Sorry I wanted to type option number A.

Ans 5:

Class : Class 8

Ans 6:

Class : Class 9
common factors are 5 and 10

Ans 7:

Class : Class 10
common factor is 5,10

Ans 8:

Class : Class 8

Ans 9:

Class : Class 7
common factor is 5,10

Ans 10:

Class : Class 4
The common factors of 40 and 70 are 2,5 and 10 which are same as common factors of 10 and 40. (2,5,10) and hence answer B is correct.

Ans 11:

Class : Class 5
the answer is 5 and 10

Ans 12:

Class : Class 4

Ans 13:

Class : Class 10

Ans 14:

Class : Class 6
actually,they are asking which one has the same relationship as 40 and 70 which is 10 and 40 so, B is the correct answer

Ans 15:

Class : Class 4
Common factors are 5 and 10 ie option B

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 8
Raj's age = x. x + 4x + ( x - 6 ) = 72, or 5x + ( x - 6 ) = 72, or 5x + x - 6 = 72, or 6x - 6 = 72, or 6x = 72 + 6, or 6x = 78 or x = 78/6 or x = 13, so Raj is 13 years old. Shilpa is 13 x 4 = 52 years old. Riya is 13 - 6 = 7 years old. Shilpa is 52 - 7 = 45 years older than Riya, so answer is B.

Ans 2:

Class : Class 10
Shilpa_Age = 4* Raj_Age --- (1) Riya_Age = Raj_Age - 6 --- (2) Shilpa_Age + Raj_Age + Riya_Age = 72 This can be rewritten as, (from (1) and (2)) 4*Raj_Age + Raj_Age + Raj_Age - 6 =72 6*Raj_Age = 78 Raj_Age = 78/6 = 13 Therefore, Shilpa_Age = 4*13 = 52 Riya_Age = 13 - 6 = 7 Therefore, Shilpa is 52 - 7 = 45 years elder than Riya Option (B)

Ans 3:

Class : Class 10
Answer: D
Solution
Let age of Shilpa, Raj and Riya be S, R, and Ri respectively
Then
S = 4R
Ri = R - 6
S + R + Ri = 72
or
4R + R + R - 6 = 72
6R = 66
R = 11
S = 44
Ri = 5
So Shilpa is (44- 5) 39 years older than Riya

Ans 4:

Class : Class 4
Riya is younger to Raj therefore she is also younger to Shilpa. let Raj be 'x' . Shilpa = 4x and Riya is x-6. {x+ 4x + x-6 = 72} or 6x - 6 =72 or 6x = 78 or x= 13

Ans 5:

Class : Class 7
45 years

Ans 6:

Class : Class 5
The step written by you 4R + R + R - 6 = 72 6R = 66 This step is wrong. As 6 will be added to 72 and NOT SUBTRACTED. hence, 6R = 78

Ans 7:

Class : Class 4
let Raj be = x yrs, Shilpa = 4x, Riya = x-6 therefore x + 4x + x-6 = 72 or 6x = 78 or x = 13 This means Raj = 13 yrs, Shilpa = 4 x 13 = 52 yrs, and Riya = 13 - 6 = 7yrs thus Shilpa is 45 yrs older to Riya (52-7 = 45)

Ans 8:

Class : Class 5
yes i am too getting 45.

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
so many

Ans 2:

Class : Class 4
Ans is A Factors of 36 & 96 are 2,3,6 &12 from the above three numbers are multiples of 3 i.e 3, 6, 12

Ans 3:

Class : Class 8
factors of 36 are 1,2,3,4,6,9,12,18,36 factors of 96 are 1,2,3,4,6,8,12,24,32,48,96 common 1,2,3,4,6,12 multiple of 3 - 3,6,12 ans is A

Ans 4:

Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.

Ans 5:

Class : Class 5
No,its 3. The common factors are 1,2,3,4,6,12. But the factors that are also multiples of 3 are 3, 6 and 12

Ans 6:

Class : Class 10
I think that 3 and 6 both are factors of 36 and 96 and multiple of 3

Ans 7:

Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.

Ans 8:

Class : Class 5
3

Ans 9:

Class : Class 9
Answer : A Solution 3,6,12 are three common factors of 36 and 96 which are also multiple of 3. Hence the answer is 3 numbers. The questions is 'how many numbers' and not 'which numbers'.

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