International Maths Olympiad Forum By SOF Olympiad Trainer - Page 111

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
the answer is C

Ans 2:

Class : Class 8
6 hrs = 6*60*60= 21600 sec 5/6 = 50/60 mins = 50* 60 = 3000 sec 21600+3000= 24600 sec

Ans 3:

Class : Class 7
please explain the answer

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4

Ans 2:

Class : Class 8

Ans 3:

Class : Class 4
F comes ahead of N therefore from the options only E comes ahead of K.

Ans 4:

Class : Class 4

Ans 5:

Class : Class 9
E: F:N::E:K

Ans 6:

Class : Class 5
R is onlyoptio

Ans 7:

Class : Class 4
what is the answer of this question

Ans 8:

Class : Class 7

Ans 9:

Class : Class 7
Since K comes before N in alphabets so ans is E because only E is coming before F in given options.

Ans 10:

Class : Class 4
Ans-B

Ans 11:

Class : Class 6

Ans 12:

Class : Class 5
F and E are made up of horizontal and vertical lines whereas N

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Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Class : Class 1
The correct answer is A.

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Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Class : Class 1
The correct answer is B.

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 9
Answer : b Solution Smallest : 4608 Largest : 4688 Numbers between smallest and largest : 4640, 4680 Sum = 4640 4680 = 9320 So B is the right answer

Ans 2:

Class : Class 10
Answer : b
Solution
Smallest : 4608
Largest : 4688
Numbers between smallest and largest : 4640, 4680
Sum = 4640+4680 = 9320
So B is the right answer

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
answer supposes to be C, why mentioned as A????

Ans 2:

Class : Class 4
The answer c only...

Ans 3:

Class : Class 8
I am agree with Angel Gomes..

Ans 4:

Class : Class 9
I also fèel so.

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 10
Answer : A. 5265
There was a mistake in the options. It has been corrected now.

Solution
Biggest 4 digit number formed from these digits = 8743
Smallest 4 digit number formed from these digits = 3478
Difference = 8743 - 3478 = 5265

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
Option A 84 m is the right answer. Solution : The area of square is 144 m as given. Hence, the side of square is 12 m. The length of one smaller square in the shaded square is 6 m. Hence the length of the rectangle is 6+6+6+6 =24 the breadth of rectangle is 6+6+6=18 The perimetre of rectangle is 2(l+b) = 2 (24+18) = 2*42 = 84 m

Ans 2:

Class : Class 4
Ans is 84. Area of the square = 12 x 12 = 144 which means 12 is the length of two sides of the square, therefore each side will be 6 and there are 14 sides. Hence the perimeter is 14 x 6 = 84

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
ooliooli

Ans 2:

Class : Class 6

Ans 3:

Class : Class 4
ans-d

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