and the total weight of 10 
is 3200 g, what is the weight of 
?
Ans 2:
Class : Class 4
3years=36 monthsEMIper month=1970EMI in three year=72920Rajat paid in advance=35000Total amount paid=70920 35000=105920......[C] is the answer............................
Ans 5:
Class : Class 8
3 years = 36 months, and EMI paid each month= 1970/-, so the total amount paid in EMI is 36 x 1970, which is 70920.
Therefore, total value of the car is 35000 + 70920 = 105920/-.
Ans 6:
Class : Class 4
A- EMI 1970 per month
3 years = 36 months
Total Amount Paid in three years
36 x 1970 = 70920
B - Rajat Paid Advance - 35000
Total Amount Paid
A +B
70920+35000= 105920
Answer is C
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Ans 4:
Class : Class 4
The common factors of 40 and 70 are 2,5 and 10 which are same as common factors of 10 and 40. (2,5,10) and hence answer B is correct.
Ans 15:
Class : Class 6
actually,they are asking which one has the same relationship as 40 and 70 which is 10 and 40 so, B is the correct answer
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Ans 1:
Class : Class 8
Raj's age = x.
x + 4x + ( x - 6 ) = 72,
or 5x + ( x - 6 ) = 72,
or 5x + x - 6 = 72,
or 6x - 6 = 72,
or 6x = 72 + 6,
or 6x = 78
or x = 78/6
or x = 13, so Raj is 13 years old. Shilpa is 13 x 4 = 52 years old. Riya is 13 - 6 = 7 years old. Shilpa is 52 - 7 = 45 years older than Riya, so answer is B.
Ans 2:
Class : Class 5
The step written by you
4R + R + R - 6 = 72
6R = 66
This step is wrong. As 6 will be added to 72 and NOT SUBTRACTED.
hence, 6R = 78
Ans 4:
Class : Class 4
let Raj be = x yrs, Shilpa = 4x, Riya = x-6 therefore x + 4x + x-6 = 72 or 6x = 78 or x = 13 This means Raj = 13 yrs, Shilpa = 4 x 13 = 52 yrs, and Riya = 13 - 6 = 7yrs thus Shilpa is 45 yrs older to Riya (52-7 = 45)
Ans 5:
Class : Class 10
Shilpa_Age = 4* Raj_Age --- (1)
Riya_Age = Raj_Age - 6 --- (2)
Shilpa_Age + Raj_Age + Riya_Age = 72
This can be rewritten as, (from (1) and (2))
4*Raj_Age + Raj_Age + Raj_Age - 6 =72
6*Raj_Age = 78
Raj_Age = 78/6 = 13
Therefore,
Shilpa_Age = 4*13 = 52
Riya_Age = 13 - 6 = 7
Therefore, Shilpa is 52 - 7 = 45 years elder than Riya
Option (B)
Ans 6:
Class : Class 10
Answer: D
Solution
Let age of Shilpa, Raj and Riya be S, R, and Ri respectively
Then
S = 4R
Ri = R - 6
S + R + Ri = 72
or
4R + R + R - 6 = 72
6R = 66
R = 11
S = 44
Ri = 5
So Shilpa is (44- 5) 39 years older than Riya
Solution
Let age of Shilpa, Raj and Riya be S, R, and Ri respectively
Then
S = 4R
Ri = R - 6
S + R + Ri = 72
or
4R + R + R - 6 = 72
6R = 66
R = 11
S = 44
Ri = 5
So Shilpa is (44- 5) 39 years older than Riya
Ans 7:
Class : Class 4
Riya is younger to Raj therefore she is also younger to Shilpa.
let Raj be 'x' . Shilpa = 4x and Riya is x-6. {x+ 4x + x-6 = 72} or 6x - 6 =72 or 6x = 78 or x= 13
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Ans 2:
Class : Class 8
factors of 36 are 1,2,3,4,6,9,12,18,36
factors of 96 are 1,2,3,4,6,8,12,24,32,48,96
common 1,2,3,4,6,12
multiple of 3 - 3,6,12
ans is A
Ans 3:
Class : Class 5
No,its 3. The common factors are 1,2,3,4,6,12. But the factors that are also multiples of 3 are 3, 6 and 12
Ans 5:
Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Ans 6:
Class : Class 4
Ans is A
Factors of 36 & 96 are 2,3,6 &12
from the above three numbers are multiples of 3 i.e 3, 6, 12
Ans 8:
Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Ans 9:
Class : Class 9
Answer : A Solution 3,6,12 are three common factors of 36 and 96 which are also multiple of 3. Hence the answer is 3 numbers. The questions is 'how many numbers' and not 'which numbers'.
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Ans 3:
Class : Class 4
The correct answer must Hospital as 3/4 turn clockwise takes to the Cinema and Hospital is opposite of the Cinema. The answer will cinema if she takes anticlockwise turn instead of clockwise
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Ans 1:
Class : Class 5
ACCORDING TO ME THE ANSWER SHOULD BE 3144 m,SINCE, 1300 m 272 m = 1572 m and 1572 m *2= 3144 m.PLEASE CHECK THE ANSWER.
Ans 2:
Class : Class 10
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Ans 3:
Ans 13:
Class : Class 9
2/8 (=10/40) in the morning left only 6/8
3/5 of 6/8 = 18/40
leftover milk is = 1-(10/40) - (18/40) = 12/40 = 3/10
Ans 16:
Class : Class 10
Answer : B
Milk left for the evening = 1 - 2/8 = 6/8
Milk consumed in the evening = 3/5 of 6/8 = 3/5 x 6/8 = 18/40
Total milk consumed = 2/8 + 18/40 = 28/40
Milk left = 1 -28/40 = 12/40 = 3/10
Milk left for the evening = 1 - 2/8 = 6/8
Milk consumed in the evening = 3/5 of 6/8 = 3/5 x 6/8 = 18/40
Total milk consumed = 2/8 + 18/40 = 28/40
Milk left = 1 -28/40 = 12/40 = 3/10
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Ans 1:
Class : Class 3
I think they are asking for the mass of all 5 balls together. The mass of small ball is 6 Kg. Hence the total mass = 12 + 6 + 6 + 6 + 6 = 36.
Ans 2:
Class : Class 10
Answer: C (36 kg)
The option C should be 36 kg and not 30 kg. Corrected the mistake.
Solution:
Let the weight of the small ball be x.
3x = 12 + x
2x = 12
x = 6
Weight of 5 balls = 12 + 6+ 6+ 6 +6 = 36kg
The option C should be 36 kg and not 30 kg. Corrected the mistake.
Solution:
Let the weight of the small ball be x.
3x = 12 + x
2x = 12
x = 6
Weight of 5 balls = 12 + 6+ 6+ 6 +6 = 36kg
Ans 4:
Class : Class 10
Answer: C (36 kg)
The option C should be 36 kg and not 30 kg. Corrected the mistake.
Solution:
Let the weight of the small ball be x.
3x = 12 + x
2x = 12
x = 6
Weight of 5 balls = 12 + 6+ 6+ 6 +6 = 36kg
The option C should be 36 kg and not 30 kg. Corrected the mistake.
Solution:
Let the weight of the small ball be x.
3x = 12 + x
2x = 12
x = 6
Weight of 5 balls = 12 + 6+ 6+ 6 +6 = 36kg
Ans 5:
Class : Class 4
left side weight is 12 + 6(small ball) = 6 + 6 + 6 ( which means 12 + 6 + 6 + 6 + 6 = 36)