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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 7
a+b=70g 10a+10b+10c=3200 10(a+b+c)=3200 a+b+c=320 c=320-70=250

Ans 2:

Class : Class 4
A

Ans 3:

Class : Class 6
If large square = A small square =B cylinder=C then, A+B=70gm 10A+10B=700gm 10C=3200gm-700gm =2500gm C=2500/10 =250

Ans 4:

Class : Class 8
250 GRAMS . FIRST DIVIDE 3200 BY 10 . ANS =320 THEN SUBTRACT 70 FROM 320. ANS =250 WEIGHT OF THE CYLINDER =250

Ans 5:

Class : Class 5
A

Ans 6:

Class : Class 4
answer is A

Ans 7:

Class : Class 4

Ans 8:

Class : Class 9
a

Ans 9:

Class : Class 4
A

Ans 10:

Class : Class 8

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 7
C

Ans 2:

Class : Class 4
3years=36 monthsEMIper month=1970EMI in three year=72920Rajat paid in advance=35000Total amount paid=70920 35000=105920......[C] is the answer............................

Ans 3:

Class : Class 4

Ans 4:

Class : Class 8
3 years = 36 months, and EMI paid each month= 1970/-, so the total amount paid in EMI is 36 x 1970, which is 70920. Therefore, total value of the car is 35000 + 70920 = 105920/-.

Ans 5:

Class : Class 4
A- EMI 1970 per month 3 years = 36 months Total Amount Paid in three years 36 x 1970 = 70920 B - Rajat Paid Advance - 35000 Total Amount Paid A +B 70920+35000= 105920 Answer is C

Ans 6:

Class : Class 4

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
Sorry I wanted to type option number A.

Ans 2:

Class : Class 10
common factor is 5,10

Ans 3:

Class : Class 10

Ans 4:

Class : Class 8

Ans 5:

Class : Class 6
actually,they are asking which one has the same relationship as 40 and 70 which is 10 and 40 so, B is the correct answer

Ans 6:

Class : Class 5
the answer is 5 and 10

Ans 7:

Class : Class 4
Common factor is 5,10

Ans 8:

Class : Class 4
The common factors of 40 and 70 are 2,5 and 10 which are same as common factors of 10 and 40. (2,5,10) and hence answer B is correct.

Ans 9:

Class : Class 10
SORRY THE ANSWER IS A

Ans 10:

Class : Class 4
A is the answer

Ans 11:

Class : Class 8

Ans 12:

Class : Class 4
Common factors are 5 and 10 ie option B

Ans 13:

Class : Class 4

Ans 14:

Class : Class 9
common factors are 5 and 10

Ans 15:

Class : Class 4
answer is 10 and 5

Ans 16:

Class : Class 7
common factor is 5,10

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
yes i am too getting 45.

Ans 2:

Class : Class 10
Answer: D
Solution
Let age of Shilpa, Raj and Riya be S, R, and Ri respectively
Then
S = 4R
Ri = R - 6
S + R + Ri = 72
or
4R + R + R - 6 = 72
6R = 66
R = 11
S = 44
Ri = 5
So Shilpa is (44- 5) 39 years older than Riya

Ans 3:

Class : Class 4
let Raj be = x yrs, Shilpa = 4x, Riya = x-6 therefore x + 4x + x-6 = 72 or 6x = 78 or x = 13 This means Raj = 13 yrs, Shilpa = 4 x 13 = 52 yrs, and Riya = 13 - 6 = 7yrs thus Shilpa is 45 yrs older to Riya (52-7 = 45)

Ans 4:

Class : Class 7
45 years

Ans 5:

Class : Class 8
Raj's age = x. x + 4x + ( x - 6 ) = 72, or 5x + ( x - 6 ) = 72, or 5x + x - 6 = 72, or 6x - 6 = 72, or 6x = 72 + 6, or 6x = 78 or x = 78/6 or x = 13, so Raj is 13 years old. Shilpa is 13 x 4 = 52 years old. Riya is 13 - 6 = 7 years old. Shilpa is 52 - 7 = 45 years older than Riya, so answer is B.

Ans 6:

Class : Class 5
The step written by you 4R + R + R - 6 = 72 6R = 66 This step is wrong. As 6 will be added to 72 and NOT SUBTRACTED. hence, 6R = 78

Ans 7:

Class : Class 10
Shilpa_Age = 4* Raj_Age --- (1) Riya_Age = Raj_Age - 6 --- (2) Shilpa_Age + Raj_Age + Riya_Age = 72 This can be rewritten as, (from (1) and (2)) 4*Raj_Age + Raj_Age + Raj_Age - 6 =72 6*Raj_Age = 78 Raj_Age = 78/6 = 13 Therefore, Shilpa_Age = 4*13 = 52 Riya_Age = 13 - 6 = 7 Therefore, Shilpa is 52 - 7 = 45 years elder than Riya Option (B)

Ans 8:

Class : Class 4
Riya is younger to Raj therefore she is also younger to Shilpa. let Raj be 'x' . Shilpa = 4x and Riya is x-6. {x+ 4x + x-6 = 72} or 6x - 6 =72 or 6x = 78 or x= 13

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
No,its 3. The common factors are 1,2,3,4,6,12. But the factors that are also multiples of 3 are 3, 6 and 12

Ans 2:

Class : Class 5
3

Ans 3:

Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.

Ans 4:

Class : Class 10
I think that 3 and 6 both are factors of 36 and 96 and multiple of 3

Ans 5:

Class : Class 4
so many

Ans 6:

Class : Class 4
Ans is A Factors of 36 & 96 are 2,3,6 &12 from the above three numbers are multiples of 3 i.e 3, 6, 12

Ans 7:

Class : Class 9
Answer : A Solution 3,6,12 are three common factors of 36 and 96 which are also multiple of 3. Hence the answer is 3 numbers. The questions is 'how many numbers' and not 'which numbers'.

Ans 8:

Class : Class 8
factors of 36 are 1,2,3,4,6,9,12,18,36 factors of 96 are 1,2,3,4,6,8,12,24,32,48,96 common 1,2,3,4,6,12 multiple of 3 - 3,6,12 ans is A

Ans 9:

Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
may i please know how cinema hall is anti clockwise

Ans 2:

Class : Class 4

Ans 3:

Class : Class 4
The correct answer must Hospital as 3/4 turn clockwise takes to the Cinema and Hospital is opposite of the Cinema. The answer will cinema if she takes anticlockwise turn instead of clockwise

Ans 4:

Class : Class 8
cinema hall

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 10
Each Albrigi tank meets an operational philosophy based on nearly thirty years of experience in the production of stainless steel systems, which has guided the company towards the application of the most modern technologies and the most advanced construction techniques. The high quality standards, supported by the almost entirely robotized production structure, complete the maximum precision of processing and finishing. All Albrigi Tecnologie tanks are fully integrated with AISI 304, AISI 304L, AISI 316 and AISI 316L austenitic steel and comply with the second highest quality standard and the most restrictive norms of the sector (GMP, FDA, 3A). These processes are added to the guarantee of the steel, a particular effectiveness and speed in the operations of maintenance and cleaning, according to the legislation. In the last ten years Albrigi Tecnologie has specialized in the food sector in particular, providing high quality systems for famous brands in the industry such as Aia, Barilla and Zuegg. Its geographical location, in the heart of Valpantena, which is part of the so-called enlarged Valpolicella, where Amarone and Recioto is produced, has made it possible, however, that Albrigi Tecnologie immediately developed an attention for the wine sector, so much so that over the years it has become one of the most successful companies in Italy also in the construction of registered plants for the storage and fermentation of wines .. The owner is Stefano Albrigi who, after a long experience in the sector, has understood the importance of investing in technological development and in in-house professional skills. For this reason, around 35% of turnover is spent on research and business improvements. For Albrigi Tecnologie the search for ever new solutions is in the first place. Among the innovations recently proposed at the latest trade fairs (Vinitaly, Simei, Sitevi), we recall Il Archimede System, control and vinification system for automation in the cellar, Picturetank and Colourtank, for a touch of liveliness in the cellar and Polifascia, economic and innovative system, an exclusive Albrigi patent to condition your existing tanks

Ans 2:

Class : Class 5
ACCORDING TO ME THE ANSWER SHOULD BE 3144 m,SINCE, 1300 m 272 m = 1572 m and 1572 m *2= 3144 m.PLEASE CHECK THE ANSWER.

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5

Ans 2:

Class : Class 4
3/10

Ans 3:

Class : Class 9
2/8 (=10/40) in the morning left only 6/8 3/5 of 6/8 = 18/40 leftover milk is = 1-(10/40) - (18/40) = 12/40 = 3/10

Ans 4:

Class : Class 6
3/20Thank you Priti Srivastav

Ans 5:

Class : Class 10
Answer : B
Milk left for the evening = 1 - 2/8 = 6/8
Milk consumed in the evening = 3/5 of 6/8 = 3/5 x 6/8 = 18/40
Total milk consumed = 2/8 + 18/40 = 28/40
Milk left = 1 -28/40 = 12/40 = 3/10

Ans 6:

Class : Class 3

Ans 7:

Class : Class 8
3/10

Ans 8:

Class : Class 4
the correct answer is 3/20 which is C

Ans 9:

Class : Class 4
Answer is option B or 3/10

Ans 10:

Class : Class 4
3/20 is correct

Ans 11:

Class : Class 5
3/10 is correct

Ans 12:

Class : Class 5
3/20

Ans 13:

Class : Class 5
Answer is C

Ans 14:

Class : Class 6
It is 3/20 because- if you add 2/8 and 3/5 =17/20 which he drank =20/20-17/20=3/20

Ans 15:

Class : Class 9

Ans 16:

Class : Class 9
blah blah blahwhatever

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 10
Answer: C (36 kg)
The option C should be 36 kg and not 30 kg. Corrected the mistake.

Solution:
Let the weight of the small ball be x.
3x = 12 + x
2x = 12
x = 6
Weight of 5 balls = 12 + 6+ 6+ 6 +6 = 36kg

Ans 2:

Class : Class 3
I think they are asking for the mass of all 5 balls together. The mass of small ball is 6 Kg. Hence the total mass = 12 + 6 + 6 + 6 + 6 = 36.

Ans 3:

Class : Class 5

Ans 4:

Class : Class 10
Answer: C (36 kg)
The option C should be 36 kg and not 30 kg. Corrected the mistake.

Solution:
Let the weight of the small ball be x.
3x = 12 + x
2x = 12
x = 6
Weight of 5 balls = 12 + 6+ 6+ 6 +6 = 36kg

Ans 5:

Class : Class 4
left side weight is 12 + 6(small ball) = 6 + 6 + 6 ( which means 12 + 6 + 6 + 6 + 6 = 36)

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Subject :IMO    Class : Class 4

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