International Maths Olympiad Forum By SOF Olympiad Trainer - Page 114
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lavanya from rimt world school, Chandigarh
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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lavanya from rimt world school, Chandigarh
Subject :IMO    Class : Class 4

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pravar from calcutta international school, Kolkata
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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Anand Mahajan from ,
Subject :IMO    Class : Class 4

Ans 1:

Admin from SOF, Noida
Class : Class 10
Answer : b
Solution
Smallest : 4608
Largest : 4688
Numbers between smallest and largest : 4640, 4680
Sum = 4640+4680 = 9320
So B is the right answer

Ans 2:

Sunita from Dps, Greater Noida
Class : Class 9
Answer : b Solution Smallest : 4608 Largest : 4688 Numbers between smallest and largest : 4640, 4680 Sum = 4640 4680 = 9320 So B is the right answer

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Yash Mehta from GIIS, Singapore
Subject :IMO    Class : Class 4

Ans 1:

NIRMAY JOSEPH from St Columba's School, New Delhi , New Delhi
Class : Class 9
I also fèel so.

Ans 2:

FIONA GOMES from LOTUS VALLEY GURGAON, Gurgaon
Class : Class 4
answer supposes to be C, why mentioned as A????

Ans 3:

Sarthak from St Anthony Senior Secondary School Hiran Magri Udaipur, Udaipur
Class : Class 8
I am agree with Angel Gomes..

Ans 4:

Priya Ponmurugan from Gateway international school, chennai
Class : Class 4
The answer c only...

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Darshan Garg from Sri Chaitanya Techno School, Bengaluru
Subject :IMO    Class : Class 4

Ans 1:

Admin from SOF, Noida
Class : Class 10
Answer : A. 5265
There was a mistake in the options. It has been corrected now.

Solution
Biggest 4 digit number formed from these digits = 8743
Smallest 4 digit number formed from these digits = 3478
Difference = 8743 - 3478 = 5265

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RAJESH DEWANGAN from ,
Subject :IMO    Class : Class 4

Ans 1:

Vrushti from swami vivekanand english primary school, Mumbai
Class : Class 4
Ans is 84. Area of the square = 12 x 12 = 144 which means 12 is the length of two sides of the square, therefore each side will be 6 and there are 14 sides. Hence the perimeter is 14 x 6 = 84

Ans 2:

sai ramakrishna GUDIMETLA  from AMM MATRICULATION HIGHER SECONDARY SCHOOL, Chennai
Class : Class 5
Option A 84 m is the right answer. Solution : The area of square is 144 m as given. Hence, the side of square is 12 m. The length of one smaller square in the shaded square is 6 m. Hence the length of the rectangle is 6+6+6+6 =24 the breadth of rectangle is 6+6+6=18 The perimetre of rectangle is 2(l+b) = 2 (24+18) = 2*42 = 84 m

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Shradha82 from Euro school , Pune
Subject :IMO    Class : Class 4

Ans 1:

Soham Gupta from JSSIS Dubai, Dubai
Class : Class 6

Ans 2:

Reshmi Arora from Lotus valley noida, Noida
Class : Class 4
ooliooli

Ans 3:

Anjala Ambade from ,
Class : Class 4
ans-d

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Kush Bansal from bbpspp, New Delhi
Subject :IMO    Class : Class 4

Ans 1:

Jiyan Domadia from Podar International School , Rajkot
Class : Class 6
IF WE TAKE 1st 4 THEN 5 AND THEN AT LAST 1 THEN IT WILL COME 22 AND PLEASE START COUNTING FROM 13 NOT FROM 11

Ans 2:

USHASHI CHAKRABARTI from INDUS VALLEY WORLD SCHOOL, CALCUTTA
Class : Class 6
Answer is supposed to be 14 , but they are NOT counting the going down through the snake ,so in that case answer should be 22[c].

Ans 3:

USHASHI CHAKRABARTI from INDUS VALLEY WORLD SCHOOL, CALCUTTA
Class : Class 6
Answer is supposed to be 14 , but they are NOT counting the going down through the snake ,so in that case answer should be 22[c].

Ans 4:

sapna from sarhad school, Pune
Class : Class 4
22

Ans 5:

PS Gour from Chirec international schoo The best 30 years and beyond, Hyderabad
Class : Class 7
answer c easy quetion

Ans 6:

naman garg from dps mathura road, delhi
Class : Class 6
Naman from DPS Mathura road DelhiI agree with you all ,answer should be 14

Ans 7:

Ibrahim Ahmed from Lady Vissanji , Mumbai
Class : Class 4
They keep changing the answers. I call it "cheating "

Ans 8:

Ibrahim Ahmed from Lady Vissanji , Mumbai
Class : Class 4
They keep changing answers. It is called "cheating".

Ans 9:

Ibrahim Ahmed from Lady Vissanji , Mumbai
Class : Class 4

Ans 10:

aaryan chandrakant sonawane from nanded city public school, Pune
Class : Class 6
actually the answer should be 14 but now he is on 10

Ans 11:

ASHIM SARKAR from ,
Class : Class 4
answer c.5+4+1=10.add 10 with 12.but the sum is wrong as per snakes and lader

Ans 12:

Anushka kumar from DPS paradip, odisa
Class : Class 9
it should be 14

Ans 13:

NACHIKET KRISHNAN from THE MODERN SCHOOL, FARIDABAD
Class : Class 6
correct answer is 14..

Ans 14:

sai ramakrishna GUDIMETLA  from AMM MATRICULATION HIGHER SECONDARY SCHOOL, Chennai
Class : Class 5
Yes, I agree with you. The answer should have been 14.

Ans 15:

Admin from SOF, Noida
Class : Class 10
The correct answer is 14.

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nridev nathawat from nms, Jaipur
Subject :IMO    Class : Class 4

Ans 1:

Sunita from Dps, Greater Noida
Class : Class 9
c

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