Subject :ICSO Class : Class 2
Subject :ICSO Class : Class 4
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Subject :ICSO Class : Class 2
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Subject :ICSO Class : Class 6
Ans 2:
Class : Class 8
Option b is correct because A and B are string variables. I mean to say Variable A has a string Value 5 and variable B has a string value 4 stored in it. Variable C which is an output variable is also a string variable bcoz it is declared as C$. So Sum=C$ means Sum=A$+B$ ,+ means concatenation. 5 and 4 are concatenated that is Sum=54.
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Subject :ICSO Class : Class 2
Match the following columns.
(A) Key used to insert spaces | (1) ![]() |
(B) Key used to insert spaces | (2) ![]() |
(C) Key used to insert spaces | (3) ![]() |
(D) Key used to insert spaces | (4) ![]() |
A (A) - (3), (B) - (4), (C) - (2), (D) - (1)
B (A) - (4), (B) - (3), (C) - (1), (D) - (2)
C (A) - (3), (B) - (2), (C) - (4), (D) - (1)
D (A) - (1), (B) - (2), (C) - (4), (D) - (3)
ALL THE OPTIONS IN COLUMN 1 ARE SAME. THIS IS A WRONG QUESTION
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Subject :ICSO Class : Class 5
Ans 1:
Class : Class 7
ans A .Divide the circle into two halves vertically.on the right half add 2 to 3 and get 5 which is on the other half{bottom}.NEXT add 3 to 4 to get 7 which is on the other half.Again add 4 to 5 to get 9 which is on the left half.So therefore 5 + 5 is 10. now you'll go to the left half and 7-5 is 2 which is on the right half.
Ans 4:
Class : Class 6
Ans B.
Because every number in the left side of the circle is one more than the double of the number in top/bottom right of the number.
Ans 5:
Class : Class 6
Ans B.
Because every number in the left side of the circle is one more than the double of the number in top/bottom right of the number.
Ans 6:
Class : Class 5
Answer B 2+3=5 on opposite 3+4=7 on opposite similarly 5+6=11 is the answer in opposite.
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Subject :ICSO Class : Class 3
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Subject :ICSO Class : Class 4
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Subject :ICSO Class : Class 6
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Subject :ICSO Class : Class 3