Subject :NSO Class : Class 10
Subject :NSO Class : Class 10
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Subject :NSO Class : Class 10
Ans 1:
Class : Class 10
The answer for this question is 0.5m/s.first you should find the initial distance of the object.then after the object is moven try to find the final position of object .you can find this by using mirror formula.after this you woul get the initial and the final positions of the object as -50m and -25m respectively.then taked the distance covered by the object as 25 and divide it by time 20sec to calculate the speed of object and finally you get your answer as 0.5m/s. HOPE THIS WILL HELP YOU.
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Subject :NSO Class : Class 10
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Subject :NSO Class : Class 10
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Subject :NSO Class : Class 10
Ans 2:
Class : Class 6
Q is a metal and S is a non metal, and therefore Q has a greater chance at losing electrons. The correct option is D.
Ans 5:
Class : Class 10
the answer for this question is option D,since Q is more electropositive than s and thus will lose electrons easily .But in the answer key it is given as optionB.
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Subject :NSO Class : Class 10
Post Your Answer
Subject :NSO Class : Class 10
Ans 1:
Class : Class 10
THE ANSWER FOR THIS QUESTION IS C.BECAUSE WHEN THE RATIO IS 3:2:1 THEN THE FIRST HYDROCARBON MUST BE A AN ALKANE .THUS OPTION ONE IS WRONG.THE SECOND OPTION WILL ALSO BE INCORRECT BECAUSE BROMIN WATER IS APPLICABLE TO UNSATURATED CARBON COMPOUNDS ,AND 2 AND 3 ARE UNSATURATED CARBON COMPOUNDS,SO OPTION TWO IS ALSO WRONG.FINALLUY THE OPTION THREE IS CORRECT AS TOLLENS TEST IS APPLICABLE TO CARBON COMPOUNDS WIT ALDEHYDE GROUP AND 2 AND 3 DOES NOT CONTAIN ALDEHYDE GROUP
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Subject :NSO Class : Class 10
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Subject :NSO Class : Class 10
The given figure shows a diagram of eye. Which of the following correctly lists the names of marked parts of the eye?
| 1 | 2 | 3 | 4 | |
|---|---|---|---|---|
| A | Pupil | Lens | Iris | Cornea |
| B | Iris | Cornea | Pupil | Lens |
| C | Pupil | Cornea | Iris | Lens |
| D | Iris | Lens | Pupil | Cornea |