Subject :NSO Class : Class 10
Subject :NSO Class : Class 10
Post Your Answer
Subject :NSO Class : Class 10
Post Your Answer
Subject :NSO Class : Class 10
Post Your Answer
Subject :NSO Class : Class 10
Post Your Answer
Subject :NSO Class : Class 10
Post Your Answer
Subject :NSO Class : Class 10
Ans 1: (Master Answer)
Class : Class 1
The correct answer is D
Current carrying wire produces magnetic field, but direction of magnetic field on the given points X and Y are different.
This is found by right hand thumb rule. So magnetic compasses on X and Yexperience magnetic force of same magnitude but in opposite directions. Hence, the needles will deflect in opposite directions.
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Subject :NSO Class : Class 10
Ans 1: (Master Answer)
Class : Class 1
The correct answer is B
Coil P is moved with a uniform speed towards Q while R is static. Due to the current in P, magnetic field is from right to left. When P is moved towards Q, magnetic lines passing through Q (from right to left) will increase, i.e., magnetic flux passing through Q will increase. Therefore, current will be induced in Q. The induced current will have such a direction that it gives a magnetic field opposite to that passing through Q due to current in P. Thus, anticlockwise current will be induced in coil Q, opposite to the direction of current in coil P.
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Subject :NSO Class : Class 10
Ans 1:
Class : Class 5
Since the residue obtained was black in colour and we know that only Zinc and Copper on reacting with Iron give a black residue hence the answer is Option D
Ans 2: (Master Answer)
Class : Class 1
Here, the answer is D.
Black residue is obtained in test tubes I and III i.e., iron gets displaced in test tubes I and III. Therefore, metals P and R should be more reactive than iron.
No change is observed in test tubes II and IV hence, metals Q and S should be less reactive than iron.