Class : Class 10
LET THE AGE OF FATHER AND SON BE X AND Y RESPECTIVELY
X+Y=60......(1)
AGE OF FATHER 6YEARS AGO WAS
X-6=5(Y-6).....(2)
X-6=5Y-30
BY USING ELIMINATION METHOD IN EQ (2)&(1) RESPECTIVELY WE GET
Y=14YEARS AND X= 44YEARS
THUS AFTER 6 YEARS THE SONS AGE WOULD BE 20 YEARS.
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Ans 1:
Class : Class 10
C. 4480 m
VOLUME OF FRUSTUM= VOLUME OF WIRE
(calculate radius using trigonometry)
R=radius of original cone, H=height of original cone, r=radius of new cone, h=height of new cone, r₁²=radius of wire, h₁=height/length of wire
vol. of frustum= vol. of original cone- vol. of smaller cone (cut off) => 1/3πR²H - 1/3πr²h => 1/3π*7000/3cm³
vol. of wire(cylinder) = πr₁²h₁ => π1/24*1/24*h
equating and cancelling on both sides of equation,
7000= h/64
h=448000cm = 4480 m
Ans 2:
Class : Class 10
C. 4480 m
VOLUME OF FRUSTUM= VOLUME OF WIRE
(calculate radius using trigonometry)
R=radius of original cone, H=height of original cone, r=radius of new cone, h=height of new cone, r₁²=radius of wire, h₁=height/length of wire
vol. of frustum= vol. of original cone- vol. of smaller cone (cut off) => 1/3πR²H - 1/3πr²h => 1/3π*7000/3cm³
vol. of wire(cylinder) = πr₁²h₁ => π1/24*1/24*h
equating and cancelling on both sides of equation,
7000= h/64
h=448000cm = 4480 m