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is equal to _____.
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Ans 1: (Master Answer)
Class : Class 1
The correct answer is C.
In ΔAED,
∠AE D + ∠EAD + 90° = 180° (Angle sum property)
⇒ ∠AED + ∠EAD = 90°
⇒ ∠EAD = 90° – ∠AED ...(i)
Also, ∠EAD = (50° + ∠AFB) ...(ii) (Exterior angle property)
From (i) and (ii), we have
50° + ∠AFB = 90° – ∠AED
⇒ ∠AFB + ∠AED = 90° – 50° = 40°
⇒ ∠AED + ∠CFD = 40°
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Ans 1: (Master Answer)
Class : Class 1
The correct anser is D.
Circumference = 24πm, Width of track= 2 m
As we know that circumference = 2πr
Therefore, 2πr = 24π
r = 12m
Now, Radius of outer circle = Radius of inner circle + Width of the track = 12 m + 2 m = 14 m
Again, Circumference of outer circle = 2πR = 2 X 3.14 X 14 = 88 m
Hence, the quantity of wire required to surround the path completely is 88 m.
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