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Subject :IMO    Class : Class 10

Ans 1:

from ,
Class :
D

Ans 2:

from ,
Class :
D Because a+b+c=0 And, a3+b3+c3=3abc

Ans 3:

from ,
Class :
Answer is 3abc cause'. Centroid in coordinate geometry is equal tO X1+X2+X3/2 , Y1+Y2+Y3/2 THEREFORE 0 EQUAL TO X CORDINATE ANT SO A+B+C EQUAL TO ZERO

Ans 4:

Vaibhav Elisetti from sri chaitanya techno school Nallagandla, Hyderabad
Class : Class 7
IT IS D BECAUSE 3abc IS equal to A CUBE+B CUBE+C CUBE

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Subject :IMO    Class : Class 10

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Shashank Jain from VCA, Dewas
Subject :IMO    Class : Class 10

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Only Π is irrational because 22/7 is a fraction in p/q form.

Ans 2:

from ,
Class :
Only Π is irrational because 22/7 is a fraction in p/q form.

Ans 3:

from ,
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Yes the correct answer is π because 22/7 is of the form p/q and if we use π the its value will be 3.14 appox it doesn't have proper value by this we can say that 22/7 is rational number and π is an irrational number

Ans 4:

Srishti Rao from Global Indian International School , singapore
Class : Class 10

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from ,
Subject :IMO    Class : Class 10

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from ,
Subject :IMO    Class : Class 10

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from ,
Subject :IMO    Class : Class 10

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from ,
Subject :IMO    Class : Class 10

Ans 1:

KETAKI SUBHASH GHATOL 2 from CSA Satara, Satara
Class : Class 10

Ans 2:

Zaara from Gyan Niketan Girls School, Patna
Class : Class 10
Sir...what would be the solution to this question

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from ,
Subject :IMO    Class : Class 10

Ans 1:

from ,
Class :
C

Ans 2: (Master Answer)

from ,
Class :

The correct answer is C.

In ΔAED, 
∠AE D + ∠EAD + 90° = 180° (Angle sum property) 
⇒ ∠AED + ∠EAD = 90° 
⇒ ∠EAD = 90° – ∠AED ...(i) 
Also, ∠EAD = (50° + ∠AFB) ...(ii) (Exterior angle property) 
From (i) and (ii), we have 
50° + ∠AFB = 90° – ∠AED 
⇒ ∠AFB + ∠AED = 90° – 50° = 40° 
⇒ ∠AED + ∠CFD = 40°


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Avinash Mishra from Central Hindu School, Gorakhpur
Subject :IMO    Class : Class 10

Ans 1: (Master Answer)

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The correct anser is D.

Circumference = 24πm, Width of track= 2 m 

As we know that circumference = 2πr
Therefore, 2πr = 24π

                   r = 12m

Now, Radius of outer circle = Radius of inner circle + Width of the track = 12 m + 2 m = 14 m
Again, Circumference of outer circle = 2πR = 2 X 3.14 X 14 = 88 m 

Hence, the quantity of wire required to surround the path completely is 88 m. 


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Subject :IMO    Class : Class 10

Ans 1:

Sahasra Shanker from KV IIT, Chennai
Class : Class 6
help

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