The diagram shows identical lamps X and Y connected in series with a battery. The lamps light with normal brightness.
If a third lamp Z is connected in parallel with lamp X, then what will happens to the brightness of the lamp Y?
A Brighter than normal
B Normal
C Dimmer than normal
D Very dim (cannot be seen)
why?
Ans 2:
Edit Post
Class : Class 10
correct answer should be option B because there is no change in the current passing through lamp Y.
Ans 3:
Edit Post
Class : Class 6
The correct answer is B as the bulb Y is in straight series and there is no change of current passing through it. And the curent gets equally divided among X and Y.
Ans 5:
Edit Post
Arunima
from
dps, Bharuch
Class : Class 6
Shouldn't the answer be option B, because it makes the most sense. No electricity or amps or power is taken away from bulb Y. Why is it answer A?
Ans 8:
Edit Post
Ans 9:
Edit Post
Ans 12:
Edit Post
Ans 16:
Edit Post
Class : Class 7
I thought of B but after checking the solution I got it that it's A only, so the answer is A
Ans 21:
Edit Post
Class : Class 6
I think (A) is the answer because the explanation in the solution makes complete sense but technically it could also be (B)
Ans 22:
Edit Post
Class : Class 10
I agree with omkar,maitri,abhid etc all who are saying option B because we can read that another bulb 'Z' is connected in "PARALLEL" and not in "SERIES" and as we know , if we connect many bulb with same battery in a parallel circuit , they will give same brightness if the one bulb was connected , but the consumption of battery will also increase.So, according to me , there will be no change in bulb y (NORMAL)ans should be : option "A"