If the question is :-
"in the figure (not drawn to scale), ABCD is a rectangle, FA = FG, AGE and BGF are straight lines. find x+y."
then the answer is:-
angle DAF is 20 degree,
angle ADF is 90 degree,
so, angle DFA = 180-(20+90)
=70 degree.
as DFC and AB are parallel,
angle DFA = angle FAB =70 degree
DA and CEB are parallel
so, angle BEA = angle EAD = 74 degree
so, angle FAG =74 - 20 =54 degree
as FAG is a isoseles triangle, angle FAG = angle FGA = 54 degree
so x = 180 -(54+54) degree
=72 degree
again, angle AGF= angle BGE = 54 degree
so, y = 180 - ( 74 + 54 )
= 180 - 128
=52 degree
as a result ( x + y ) = 72 + 52 =124 degree (option B).
THANK YOU