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Nirabhra from bluebells international, New Delhi
Subject :Sam    Class : Sample

The given diagram shows a series of images of a moving ball captured by a camera.

The ball was moving at a constant velocity and the images were taken at a constant rate of 10 per second. What is the speed of the ball?

A30 ms-1
B20 ms-1
C45 ms-1
D15 ms-1


i am unable to understand how

Ans 1:

MRITTIKA DAS from KENDRIYA VIDYALAYA, GANGTOK, GANGTOK
Class : Class 3

Ans 2:

Sufiya from Vidhyashram international school Jodhpur , Jodhpur
Class : Class 7

Ans 3:

RAHUL SINHA from D.A.V Public Koyla Nagar Dhanbad, dhanbad
Class : Class 7
Speed=distance /time But the answer is 30 m/s^-1

Ans 4:

Aditya kaushik from Delhi Public School Bhilai, Bhilai
Class : Class 9
speed = distance/time

Ans 5:

itanya from Manav Rachna International School, Ludhiana
Class : Class 7
how to solve this question

Ans 6:

Aditya from Bvb vidyashram, Jaipur
Class : Class 8
thanks kashvi I now really understand how to solve these type of questions . Very good explanation.

Ans 7:

Ashwath from Green Park Senior Secondary School , Namakkal
Class : Class 10
How to solve this question

Ans 8:

Kashish Kathuria from Delhi Public School, Bangalore
Class : Class 9
kasha and tamana thanks for explanation

Ans 9:

Nishant Borah from SHRIMANTA SHANKAR ACADEMY, Guwahati
Class : Class 9
ANS NO.6 IS NOT AT ALL CLEAR

Ans 10:

Chinmay Pathak from Navy Children School, Ernakulam
Class : Class 7
Time taken to shoot 10 images is 1 secTime taken to shoot 6 images is 0.6 sec.Assuming that the full revolution of ball is not considered thenSpeed = distance/time= 15/0.6= 25m/sIf we consider that in five shots the ball has exactly done two revolution then we have to also consider that it has travelled only 12.5 MTS.Then the speed is 12.5/0.5=25 m/s

Ans 11:

kashvi from Amity, noida
Class : Class 7
Given .. (1) time taken to take 10 shots=1 sec ==> time taken to take one shot= 1/10 sec (2) Distance travelled by ball while camera took 6 shots =15 meter We know , speed= distance/time Distance=15m Time= Not known... lets find out the time to take six shots Fist shot was taken after = 0sec (as first short was taken at beginning) Second shot taken after = 1*(1/10) = 1/10 seconds Third short taken after = 2*(1/10) =2/10 seconds Similarly .. sixth shot taken after = 5*(1/10) =5/10 Now.. speed = distance/time = 15 / (5/10) = 30 m/second Hope, it helps.

Ans 12:

niketh from dps east, bangalore
Class : Class 6
thank you answer 11 was very clear and understandable

Ans 13:

Agrani from St. Karen's Secondary School, Patna
Class : Class 7
PLEASE TELL THE SOLUTION

Ans 14:

Pulkit Gupta from Maxfort School, New Delhi
Class : Class 7
nice explanation from kashvi and tamanna de

Ans 15:

tamanna de from K.V.Kailashahar, kailashahar
Class : Class 7
time taken to shoot 10 images=1 second.time taken to shoot 5 images=5/10=1/2seconds.speed=distance/time=15divided by 1/2=15*2=30m/s

Ans 16:

Akhilesh Kancharla from International Educational Academy, Hyderabad
Class : Class 7
a

Ans 17:

ggggv from british english school, gaya
Class : Class 7
how to solve it?

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