Read the statement carefully. State ‘T’ for true
and ‘F’ for false.
(i) The diagonal BD of a parallelogram ABCD
intersect the line segment AE at the point F,
where E is any point on the side BC. Then
DE × EF = FB × FA.
(ii) ABCD is a parallelogram. If P is a point on
side BC and DP when produced meets AB
at L, then 
.
| (i) | (ii) | |
|---|---|---|
| A | T | F |
| B | F | F |
| C | T | T |
| D | F | T |
part (i) DF is incorrectly written