In the given figure, PA ⊥ AB, QB ⊥ AB and ΔOAP ≅ ΔOBQ, then
A PA = OB
B AP = BQ
C AP = BQ
D OA = OQ
In the given figure, PA ⊥ AB, QB ⊥ AB and ΔOAP ≅ ΔOBQ, then
A PA = OB
B AP = BQ
C AP = BQ
D OA = OQ