In the given figure, ΔABC and ΔPBC are two isosceles triangles on the same base BC and vertices A and P are on the same side of BC. A and P are joined, then
A
B
C
D ∠BAP = 2∠BAC
In the given figure, ΔABC and ΔPBC are two isosceles triangles on the same base BC and vertices A and P are on the same side of BC. A and P are joined, then
A
B
C
D ∠BAP = 2∠BAC