Subject :IMO Class : Class 7
An elevator descends into a mine shaft at the rate of 8 m/min. If the descend starts from 12 m above the ground level, how long will it take to reach –468 m?
A 60 mins
B 30 mins
C 50 mins
D 10 mins
Option A as -468m 12m = 480m (overall distance to be covered) and then divide it by 8 as the distance covered by elevator in 1 minute is 8. So, -480/8 = 60. Overall equation is (-468) (-12)=480/8=60 minutes. Thank You.K.V.Bargarh.
Ans 1:
Class : Class 8