A solid ball is released from the top of a slope as shown in the figure.
What will happen to the ball's kinetic and potential energy as it slips down the slope at a constant speed?
| Kinetic energy |
Potential energy |
|
|---|---|---|
| A | Increases | Decreases |
| B | Remains unchanged |
Decreases |
| C | Increases | Increases |
| D | Remains unchanged |
Remains unchanged |
Ans 1:
Class : Class 7
Option A is correct option. At the top GPE will be maximum and at the bottom of ramp GPE will be zero.At the top, KE will be zero and at the bottom KE will be maximum.Solution given is incorrect. Acceleration is constant not the speed of ball.
Ans 2:
Class : Class 6
actually, its given constant speed so b is correct as kinetic energy increases only when the speed increase
Ans 3:
Class : Class 6
OPTION A AS ITS NOT POSSIBLE FOR KE TO BE UNCHANGED IF GPE DECREASES AS ENERGY CANNOT BE CREATED NOR DESTROYED. THE GPE SHOULD BE CONVERTED INTO KE AS AT THE BOTTOM, KE IS MAX AND GPE IS 0 AND VICE VERSA ON THE TOP
Ans 4:
Class : Class 6
ALSO, IT CANNOT BE CONSTANT SPEED IF SPEED IS 0 AT THE TOP BECAUSE OTHERWISE THE BALL WOULD NOT MOVE BECAUSE ITS SPEED IS 0M/S
Ans 7:
Class : Class 6
A is correct as the kinetic energy will increase when going down the slope. It is the thing of ramps