Subject :IMO Class : Class 9
The factors of 8a3 + b3 - 6ab + 1 are
A (2a + b - 1)(4a2 + b2 + 1 - 3ab - 2a)
B (2ab - b + 1)(4a2 + b2 - 4ab + 1 - 2a + b)
C (2a + b + 1)(4a2 + b2 + 1 - 2ab - b - 2a)
D (2a - 1 + b)(4a2 + 1 - 4a - b - 2ab)
please also give the solution of this question
Ans 1:
Class : Class 9