Subject :IMO Class : Class 9
Following are the steps of construction of a ΔPQR, given that QR = 3 cm, ∠PQR = 45° and QP - PR = 2 cm. Arrange them and select the correct option.
(i) Make an angle XQR = 45° at point Q of base QR.
(ii) Join SR and draw the perpendicular bisector of SR say AB.
(iii) Draw the base QR of length 3 cm.
(iv) Let bisector AB intersect QX at P. Join PR.
(v) Cut the line segment QS = QP - PR = 2 cm from the ray QX.
A (iii) → (ii) → (i) → (v) → (iv)
B (iii) → (i) → (ii) → (v) → (iv)
C (iii) → (i) → (ii) → (iv) → (v)
D (iii) → (i) → (v) → (ii) → (iv)