Subject :IMO Class : Class 6
Match the figures given in Column-I with
their shaded ratio given in Column-II and select the correct option.
A(P) → (iii), (Q) → (iv), (R) → (i), (S) → (ii)
B(P) → (iv), (Q) → (iii), (R) → (ii), (S) → (i)
C(P) → (iv), (Q) → (iv), (R) → (i), (S) → (ii)
D(P) → (iii), (Q) → (ii), (R) → (iv), (S) → (i)
Ans 1:
Class : Class 9
Ans 2:
Class : Class 8
SOF, please modify the options.
Ans 3:
Class : Class 6
Solution(P) Total number of equal parts = 12 Number of shaded parts = 6 Shaded ratio = 6 : 12 = 1 : 2 (Q) Total number of equal parts = 8 Number of shaded parts = 4 Shaded ratio = 4 : 8 = 1 : 2 (R) Total number of equal parts = 10 Number of shaded parts = 6 Shaded ratio = 6 : 10 = 3 : 5 (Q) Total number of equal parts = 13 Number of shaded parts = 7 Shaded ratio = 7 : 13 Solution(P) Total number of equal parts = 12 Number of shaded parts = 6 Shaded ratio = 6 : 12 = 1 : 2 (Q) Total number of equal parts = 8 Number of shaded parts = 4 Shaded ratio = 4 : 8 = 1 : 2 (R) Total number of equal parts = 10 Number of shaded parts = 6 Shaded ratio = 6 : 10 = 3 : 5 (Q) Total number of equal parts = 13 Number of shaded parts = 7 Shaded ratio = 7 : 13
Ans 4:
Class : Class 8
How can 2 things in column 1 be equal to one thing in column 2? There was no mention that this is possible. Please rectify SOF