Subject :NSO Class : Class 8
A stone which has a mass of 12 g and a density
of 3 g cm-3, is lowered into 20 cm3 of water in a
measuring cylinder. What will be the new reading
on the measuring cylinder?
A 20 cm3
B 24 cm3
C 40 cm3
D 16 cm3
Ans 1:
Class : Class 8
How the answer is (b)???
Ans 2:
Class : Class 10
B
Ans 3:
Class : Class 8
The volume of the stone is equal to the volume of the water increased in the measuring cylinder.
The volume of the stone is calculated from the formula Volume =Mass/Density.
In this case, the Mass = 12 g and Density = 3g cm^3
Volume = 12/3 = 4 cm^3
The actual volume of liquid in the measuring cylinder is
20cm^3
.
So, the increase in volume will show a new reading of
20cm3+4cm3=24cm^3
hence...answer is (B)