The greatest number which divides 615 and 963, leaving the remainder 6 in each case is ______ . A86 B87 C88 D89
(B): Number dividing 615 and 963 leaving a remainder of 6 should be factor of 609 (= 615 - 6) and 957 (= 963 - 6) HCF (609, 957) = 87