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pooja shankar from KK Anand Smart Academy, Chennai
Subject :NSO    Class : Class 8

The sliding frictional force between a 4 kg box and the floor is 15 N. It is pushed across the floor with a constant force such that it accelerates at 0.8 ms-2.
If this same force calculated is applied to the box which is now placed on a frictionless floor what is the new acceleration produced?

A 8.2 ms-2
B 16.2 ms-2
C 4.6 ms-2
D 2.3 ms-2


please tell me the answer, also has everybody received the mock papers for second level?

Ans 1:

Apoorva106 from Little Angels Sr. Sec. School, Sonepat
Class : Class 8
we know that force = mass * acceleration here, mass = 4 kg and acceleration = 0.8 m/s so force = 4 * 0.8 = 3.2 N and frictional force = 15 N So total force acting on it = 15 + 3.2 = 18.2 N

Ans 2:

Bhagyesh Kamal from DPS, Mumbai
Class : Class 8

Ans 3:

Bhagyesh Kamal from DPS, Mumbai
Class : Class 8

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