Two fixed point masses of 10 kg and 20 kg are located at (0 m, 0 m) and (5 m, 0 m). Where should a third point mass of 30 kg be kept so that the net force of attraction on 30 kg mass due to point masses 10 kg and 20 kg is zero?
A At 2.05 m from 10 kg mass
B At 2.05 m from 20 kg mass
C At 2.95 m from 10 kg mass
D At 3 m from 20 kg mass
I got stuck at x^2 10x - 25Answer by quadratic equation must be 2.07 but it is 2.05Please help me with this question