User Forum

Subject :NSO    Class : Class 8

On dividing 2272 as well as 875 by 3digit number N, we get the same remainder. The sum of the digits of N is

(A) 10

(B) 11

(C) 12

(D) 13

Ans 1:

Class : Class 8
2272-875= perfectly divisible by N, 1397=multiple of N, factorisation of 1397 = 11*127, as 127 is a 3 digit no., N = 127, 1+2+7=10

Post Your Answer