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DRAVIT GUPTA from Mother's Global School, New Delhi

Subject :NSO Class : Class 9

A cavity of radius R/2 is created in a sphere of radius R and mass M at the periphery and this mass is placed at a distance 2R from the centre of the sphere as shown in figure. The force between the two is

A

B

C

D

View All Answers (4)

Ans 1:

Kshithy G Nair from Chinmaya Vidyalaya Tripunithura, Kochi

Class : Class 7

i think the above explanation is good and would be more accurate if shft of centre of mass is calculated

Ans 2:

Gh from Mahatma, Ghaziabad

Class : Class 10

I think it should be 7GM^2/256R^2 G is constant. M will become 7M/8 due to mass removal .M2 will be M/8 . Distance is 2 R . So the product is equivalent to the above. But I don't know how it is not in answers

Ans 3:

pratham from Indian School Ghubra, Muscat, Muscat

Class : Class 7

I agree with Gh from Mahatma, Ghaziabad, options are not correctly provided in the question.

Ans 4:

divanshi from sacred heart convent school, barnala

Class : Class 4

this need more details as the question is not clear