In a zoo, there were 15 lions and peacocks altogether. The number of heads was 25 less than the number of legs. How many more peacocks were there?
(A) 20
(B) 15
(C) 10
(D) 5
how answer d came
Ans 1:
Class : Class 10
Answer : D
Solution
Let number of peacocks be p
Let number of lions be l
Number of legs = 15
Number of heads = 15 + 25 = 40
p + l = 15
2p + 4l = 40
Solving the above equations
p = 10 , l = 5
So there are 5 more peacocks than lions.
Solution
Let number of peacocks be p
Let number of lions be l
Number of legs = 15
Number of heads = 15 + 25 = 40
p + l = 15
2p + 4l = 40
Solving the above equations
p = 10 , l = 5
So there are 5 more peacocks than lions.
Ans 2:
Class : Class 4
Heads ( Lions + Peacocks) = 15, No. of Legs = 25 +15 = 40. Since total legs were 40 no. of lions has to be less than 10 (because 10 x 4 legs = 40 which means zero peacock, which is not possible...) . so if we take 5 lions and 10 peacocks, total heads = 15 & total legs = 5 x 4 + 10 x 2 = 40 legs. Thus the answer is 5 peacocks were more than lions.