Aditya Sai Vemparala
from
Amanora school, Pune
Subject :IMO Class : Class 7
In the given figure, the area of the shaded portion is
A308 cm2
B462 cm2
C154 cm2
D150 cm2
Answer is c
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AYUSHMAN JAY
from
KV1 school, KANPUR
Class : Class 7
Option C is correct ,as , area of big semi circle = 14 * 14 * 22/(7*2) = 14 * 22 = 308 then we will subtract the area of unshaded 2 semi circle(which is a whole circle ), = 7 * 7 * 22/7 = 7*22 = 154 ,Hence , area of shaded portion is , = area of big semi circle - are of two small semi circle = 308 - 154 = 154 sq. cm
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Hemant Kumar Arora
from
Rockwell International School, Hyderabad
Class : Class 8
c is correct308-154=154 you have done this308 154=462hence option c is correct
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dhirendra
from
Shri O P Jindal Vidya Niketan, Mundra Kutcch
Class : Class 4
option C,154 is correct answer
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Ditya Goel
from
Presidium, Gurgaon
Class : Class 8
Answer is (C)Diameter of bigger circle=28 cmradius=28/2=14 cmArea of semicircle=1/2*22/7*14*14=4312/14=308 sq.cm2 semicircle=circleArea=22/7*7*7=1078/7=154 sq.cmArea left=308-154=154 cm
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Devavrat Sharma
from
Podar International School Powai, Mumbai
Class : Class 7
its C. as 1/2 x 22/7 x 196 - 22/7 x 49 = 154 cm2
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Prisha Hemchandra Lokhande
from
NPS Whitefield, Bangalore, Bangalore
Class : Class 8
I think C is the correct answer... 154
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Sampurna Mandal
from
DAV Public School Jagganath Talcher, Angul
Class : Class 8
Here the given answer option D is wrong . The correct answer is option C.