1. Home
  2. / Forum

User Forum

Ask Your Question
debangshi das from Springdale High School, Kalyani
Subject :IMO    Class : Class 3

Adil, Janak and Rohit gained 59 points in a game. Adil gained 2 points more than Janak. Rohit gained 9/5 of the points gained by Janak. How many points did Adil gain?

A10
B17
C20
D22


how to solve this

Ans 1:

sklogic from SSM School, Chennai
Class : Class 3
Let Janak points = J | Adil A = J + 2 | Rohit R = (9/5) * J | Adil + Janak + Rohit = 59 | A + J + R = 59 | Replace as above | (J + 2) + J + (9/5)*J = 59 | 2J + 2 + 9J/5 = 59 | To remove 5 in denominator, multiply entire equation by 5 | 10J + 10 + 9J = 295 | 19J = 295 - 10 | 19J = 285 | J = 15 | Hence Janak's points = 15 | => Adil = J + 2 = 17 points |

Ans 2:

LALIT MANI from K R Mangalam World School, New Delhi
Class : Class 6
how will we solve this?

Ans 3:

Darsh Vijay from The Orbis School, Pune
Class : Class 5

Ans 4:

LALIT MANI from K R Mangalam World School, New Delhi
Class : Class 6
Got it

Ans 5:

Riddhiraj Saha from St. Xeviers Institution , Panihati, Kolkata
Class : Class 8
how will i solve this problem?

Ans 6:

Darsh Vijay from The Orbis School, Pune
Class : Class 5

Ans 7:

Aryan Goyal from DPS , Dwarka, New Delhi
Class : Class 3
how did you get the answer

Ans 8:

Sai Lakshmi Rao from Maneckji Cooper Education Trust, Mumbai
Class : Class 4
Shouldnt it be 15? The equation is (X 2) X [(9/5)X] = 59

Post Your Answer