Mayank had a bottle of milk. He drank 2/8 in the morning and drank 3/5 of the remainder in the evening. What fraction of the original amount of milk did he have left?
(A) 2/5
(B) 3/10
(C) 3/20
(D) 3/5
Need explanation
Ans 1:
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Class : Class 9
2/8 (=10/40) in the morning left only 6/8
3/5 of 6/8 = 18/40
leftover milk is = 1-(10/40) - (18/40) = 12/40 = 3/10
Ans 2:
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Admin
from
SOF, Noida
Class : Class 10
Answer : B
Milk left for the evening = 1 - 2/8 = 6/8
Milk consumed in the evening = 3/5 of 6/8 = 3/5 x 6/8 = 18/40
Total milk consumed = 2/8 + 18/40 = 28/40
Milk left = 1 -28/40 = 12/40 = 3/10
Milk left for the evening = 1 - 2/8 = 6/8
Milk consumed in the evening = 3/5 of 6/8 = 3/5 x 6/8 = 18/40
Total milk consumed = 2/8 + 18/40 = 28/40
Milk left = 1 -28/40 = 12/40 = 3/10
Ans 4:
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Ans 6:
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from
, Allahabad
Class : Class 6
It is 3/20 because-
if you add 2/8 and 3/5 =17/20 which he drank
=20/20-17/20=3/20