Look at the given number bond.
Q is 1 more than P.
Then, P + Q = _______.
A1
B5
C6
D9
can someone explain how to solve this ?
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Class : Class 5
Got it... 64 is sum of all three. Reduce 3*5= 15 to get 49.If P = 4 and Q = 5 (as it is given that Q is one more than P), we get the sum 49.Now P Q = 4 5 = 9
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Class : Class 6
This is very difficult for class 3... it will be helpful if you could explain the answer
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from
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I am a 7th class student and i can do this question and it is a linear equation question but for class 3 it is too tough btw solution is :- as 3*5+ 6*p+ q5= 64 and q is 1 + p let p be x and q be x+1 so then equation forms =64=3*5 + 6*x + 5*(x+1) =64 =15+6x+5x+5 = 64 =20+11x so 11x = 64-20 / 11 = 44/11 ie 4 hence x=4 x+1=5 so p+q =4+5 ie9 so answer is 9. hope this helps