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Achintya k j
from
KENDRIYA VIDYALAYA GOLE MARKET, NEW DELHI
Subject :
IMO
Class :
Class 7
In the following figure, if AB = AC, then x is
A
80°
B
70°
C
60°
D
110°
please explain
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D
Keshav
from
RPS , Mahendergarh
Class :
Class 7
D
Ans 2:
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d
from
DPS R.K. PURAM,
Class :
Class 9
d
Ans 3:
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Angle BAC = x + 40 - x => 40 As triangle ABC is an isosceles triangle with AB = AC, angle acb = angle abc = x Therefore, as angle abc + angle acb + angle bac = 180 then, x + x + 40 = 180 =>2x = 180 - 40 =>2x = 140 =>x = 70
from
, Kolkata
Class :
Class 9
Angle BAC = x + 40 - x => 40 As triangle ABC is an isosceles triangle with AB = AC, angle acb = angle abc = x Therefore, as angle abc + angle acb + angle bac = 180 then, x + x + 40 = 180 =>2x = 180 - 40 =>2x = 140 =>x = 70
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