Subject :NCO Class : Class 3

Subject :NCO Class : Class 2

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Subject :NCO Class : Class 4

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Subject :NCO Class : Class 2

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Subject :NCO Class : Class 6

## Ans 1:

Class : Class 8

Option b is correct because A and B are string variables. I mean to say Variable A has a string Value 5 and variable B has a string value 4 stored in it. Variable C which is an output variable is also a string variable bcoz it is declared as C$. So Sum=C$ means Sum=A$+B$ ,+ means concatenation. 5 and 4 are concatenated that is Sum=54.

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Subject :NCO Class : Class 2

**Match the following columns. **

(A) Key used to insert spaces | (1) |

(B) Key used to insert spaces | (2) |

(C) Key used to insert spaces | (3) |

(D) Key used to insert spaces | (4) |

A (A) - (3), (B) - (4), (C) - (2), (D) - (1)

B (A) - (4), (B) - (3), (C) - (1), (D) - (2)

C (A) - (3), (B) - (2), (C) - (4), (D) - (1)

D (A) - (1), (B) - (2), (C) - (4), (D) - (3)

ALL THE OPTIONS IN COLUMN 1 ARE SAME. THIS IS A WRONG QUESTION

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Subject :NCO Class : Class 5

## Ans 1:

Class : Class 6

Ans B.
Because every number in the left side of the circle is one more than the double of the number in top/bottom right of the number.

## Ans 3:

Class : Class 7

ans A .Divide the circle into two halves vertically.on the right half add 2 to 3 and get 5 which is on the other half{bottom}.NEXT add 3 to 4 to get 7 which is on the other half.Again add 4 to 5 to get 9 which is on the left half.So therefore 5 + 5 is 10. now you'll go to the left half and 7-5 is 2 which is on the right half.

## Ans 4:

Class : Class 6

Ans B.
Because every number in the left side of the circle is one more than the double of the number in top/bottom right of the number.

## Ans 5:

Class : Class 5

Answer B 2+3=5 on opposite 3+4=7 on opposite similarly 5+6=11 is the answer in opposite.

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Subject :NCO Class : Class 3

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Subject :NCO Class : Class 4

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Subject :NCO Class : Class 6